Posted by **Akbar** on Monday, April 9, 2012 at 3:50pm.

In a hydraulic lift, the radii of the pistons are 2.93 cm and 10.1 cm. A car weighing W = 11.0 kN is to be lifted by the force of the large piston.

(a) What force Fa must be applied to the small piston? N

(b) When the small piston is pushed in by 10.4 cm, how far is the car lifted?

mm

(c) Find the mechanical advantage of the lift, which is the ratio W / Fa.

I really don't understand how to do this please explain step for step how to do this! I would really appreciate it, thank you.

- Physics -
**Elena**, Monday, April 9, 2012 at 4:06pm
a.

F1/A1 =F2/A2,

A =πR^2,

Fa = W•(r/R)^2 = 11000•(2.93/10.1)^2 = =925.7 N

b.

h2 = h1•(A1/A2) = h1•(r/R) = 3.02 cm

b.

MA = W/Fa = 11000/925.7 =11.9

- Physics to Elena -
**Akbar**, Monday, April 9, 2012 at 5:18pm
Thanks for your help, I really appreciate it! The only thing I was wondering about is part b) it says its wrong i know it's 3.02 cm, but the answer has to be in mm i got that that would be 30.2 mm, but still its wrong can you please say why I am getting it wrong?

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