Elle is pushing a box of mass 7.0 kilograms with the force of 25 newtons. If the force of friction is 2.6 newtons, what is the value of acceleration of the box?
F-F(fr) = m•a
a =(F-F(fr))/m =(25 – 2.6)/7 =3.2 m/s^2
To find the acceleration of the box, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.
Given:
Mass of the box (m) = 7.0 kilograms
Force applied by Elle (F) = 25 newtons
Force of friction (Ffriction) = 2.6 newtons
The net force acting on the box can be found by subtracting the force of friction from the applied force:
Net Force (Fnet) = F - Ffriction
Substituting the given values into the equation:
Fnet = 25 N - 2.6 N
Fnet = 22.4 N
Now, we can calculate the acceleration of the box:
Acceleration (a) = Fnet / m
Substituting the values into the equation:
a = 22.4 N / 7.0 kg
a ≈ 3.20 m/s²
Therefore, the value of acceleration of the box is approximately 3.20 m/s².
To find the acceleration of the box, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The formula for Newton's second law is:
Fnet = m * a
where Fnet is the net force, m is the mass of the object, and a is the acceleration.
In this case, the net force is calculated by subtracting the force of friction (Ffriction) from the applied force (Fapplied):
Fnet = Fapplied - Ffriction
Given that Fapplied is 25 newtons and Ffriction is 2.6 newtons, we can substitute these values into the formula:
Fnet = 25 N - 2.6 N
Now, we need to calculate the net force:
Fnet = 22.4 N
Now that we have the net force, we can rearrange Newton's second law formula to solve for acceleration:
Fnet = m * a
a = Fnet / m
Substituting the values, we get:
a = 22.4 N / 7.0 kg
a ≈ 3.2 m/s²
Therefore, the value of the acceleration of the box is approximately 3.2 m/s².