Posted by **Kara** on Monday, April 9, 2012 at 2:47pm.

An airplane leaves an airport and flies due west 150 miles and then 230 miles in the direction S 39.67 degrees W. How far is the plane from the airport at this time to the nearest mile.

- Pre Cal -
**Henry**, Tuesday, April 10, 2012 at 10:27pm
.id=150 Mi @ 180Deg. + 230 Mi @ 230.33Deg

X=150*cos180 + 230*cos230.33=-296.82 Mi

Y=150*sin180+230*sin230.33 = -177.04 Mi

d = sqrt((-296.82)^2+(-177.04)^2) = 346 Miles.

- Pre Cal -
**Limy**, Wednesday, September 24, 2014 at 10:51pm
v = -(170 + 240 sin(69.5)) i - 240 cos(69.5) j .... is the resulting vector

|| v || = √((170 + 240 sin(69.5))² + (240 cos(69.5))²)

= 403.64892 mi

Answer: 404 mi

## Answer this Question

## Related Questions

- trig - an airplane leaves the airport and flies due west 150 miles and then 240 ...
- Math/Trig - An airplane leaves an airport and flies due west 150 miles and then ...
- Math - An airplane leaves the airport and flies due west 170 miles and then 240 ...
- Physics - The pilot of a small plane finds that the airport where he intended to...
- Algebra II - An airplane leaves airport A and flies 200 km. At this time its ...
- Algebra II - An airplane leaves airport A and flies 200 km. At this time its ...
- Math 9 - 2 planes leave the airport at the same time. Minutes later plane A is ...
- pre calculus - A airplane is 145 miles North and 85 miles west of an airport. ...
- Math - Two airplanes at 25,000 ft above the ground are flying toward the same ...
- Math - A plane flies due east for 120 km from airport a to airport b it then ...