Posted by **Carlton** on Monday, April 9, 2012 at 2:41pm.

Suppose that a department contains 13 men and 19 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men

- Discreate Math -
**MathMate**, Monday, April 9, 2012 at 4:42pm
Define n choose r as (n,r)=n!/(r!(n-r)!)

Number of ways to choose 2 men and 4 women

=(13,2)*(19,4)

Number of ways to choose 1 man and 5 women

=(13,1)*(19,5)

Number of ways to choose 0 man and 6 women

=(13,0)*(19,6)

Total=?

## Answer This Question

## Related Questions

- math - Suppose that a department contains 11 men and 19 women. How many ways are...
- discrete math - Suppose that a department contains 10 men and 17 women. How many...
- discrete math - Suppose that a department contains 10 men and 17 women. How many...
- statistics - Suppose that a department contains 8 men and 20 women. How many ...
- math - A department contains 13 men and 20 women. How many ways are there to ...
- math - A department contains 12 men and 17 women. How many ways are there to ...
- business math - out of 7 men and 5 women, 5 members of a committee are selected...
- gr12 math - froma group of 6 ladies and 4 men, determine in how many ways a ...
- math - from a group of women and 4 men, determine in how many ways a committee ...
- statistics permutations and combinations - Selecting a committee: There are 7 ...

More Related Questions