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March 27, 2017

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Suppose that a department contains 13 men and 19 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men

  • Discreate Math - ,

    Define n choose r as (n,r)=n!/(r!(n-r)!)

    Number of ways to choose 2 men and 4 women
    =(13,2)*(19,4)
    Number of ways to choose 1 man and 5 women
    =(13,1)*(19,5)
    Number of ways to choose 0 man and 6 women
    =(13,0)*(19,6)

    Total=?

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