Posted by **Carlton ** on Monday, April 9, 2012 at 2:41pm.

Suppose that a department contains 13 men and 19 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men

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**MathMate**, Monday, April 9, 2012 at 4:42pm
Define n choose r as (n,r)=n!/(r!(n-r)!)

Number of ways to choose 2 men and 4 women

=(13,2)*(19,4)

Number of ways to choose 1 man and 5 women

=(13,1)*(19,5)

Number of ways to choose 0 man and 6 women

=(13,0)*(19,6)

Total=?

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