Two point charges are separated by 8 cm. The attractive force between them is 14 N. If the two charges attracting each other have equal magnitude, what is the magnitude of each charge?

okay great!!! Thank you again!!!!

you do a wonderful job!!!!

According to the definition electric field strength is E =F/q, therefore,

E = 2.4•10^-7/6•10^-13 = 4•10^-5 V/m

SORRY!

E = 2.4•10^-7/6•10^-13 = 4•10^+5 V/m

Two point charges repel each other with a force of 100N.One of the charges is increased by 10o/o and other is requced by 10o/o.the new force of repulsion at the same distance would be..

a.99N
b.125N
c.250N
d.300N

Thank you so much Elena that helped me out a lot!

I was wondering if you could also help me with another question.

A droplet of ink in an industrial ink-jet printer carries a charge of 6 10-13 C and is deflected onto paper by a force of 2.4 10-7 N. Find the strength of the electric field to produce this force.

its looking for the N/C I got 4*10^-21 but I'm not getting it correct

Coulomb’s law

F = k•q1•q2/r^2 = k•q^2/r^2
q = r•sqrt(F/k) = 0.08•sqrt(14/9•10^9)= 3.16•10^-6 C = 3.16 microC