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July 31, 2014

July 31, 2014

Posted by **febie** on Monday, April 9, 2012 at 4:23am.

- math -
**Reiny**, Monday, April 9, 2012 at 9:20amsurface area = πr^2 + 2πrh = 3π

r^2 + 2rh = 3

h = (3 - r^2)/(2r)

V = πr^2h = (πr/2)(3-r^2)

= (3π/2)r - (π/2)r^3

dV/dr = 3π/2 - (3/2)πr^2

= 0 for a max/min of V

(3π/2)r^2 = 3π/2

r^2 = 1

r = ± 1, but r > 0

r = 1

then h = (3-1)/2 = 1

check my arithmetic

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