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December 21, 2014

December 21, 2014

Posted by **D.S.** on Monday, April 9, 2012 at 1:57am.

So what I've done is rewritten it as:

(3x-7)ln10e = ln5

Now I'm a little lost as to what to do next...

- Math -
**Momito**, Monday, April 9, 2012 at 2:51amFind the value of in10 and in5

multiply the value of in10 wit the varables in the brackets

collect the like terms i.e live the varable with the x term on the left hand side and the others on the right

then solve for x from there.

Goodluck

- Math -
**Reiny**, Monday, April 9, 2012 at 8:42amYour start was incorrect...

the exponent does not apply to the 10, only to the base of e

so ...

e^(3x-7) = 5/10= .5

now take ln of both sides

(3x-7) ln e = ln .5 , but ln e = 1

3x-7 = ln .5

3x = 7 + ln .5

x = (7 + ln .5)/3 , and it is button-pushing time

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