Posted by **D.S.** on Monday, April 9, 2012 at 1:57am.

10e^(3x-7)= 5

So what I've done is rewritten it as:

(3x-7)ln10e = ln5

Now I'm a little lost as to what to do next...

- Math -
**Momito**, Monday, April 9, 2012 at 2:51am
Find the value of in10 and in5

multiply the value of in10 wit the varables in the brackets

collect the like terms i.e live the varable with the x term on the left hand side and the others on the right

then solve for x from there.

Goodluck

- Math -
**Reiny**, Monday, April 9, 2012 at 8:42am
Your start was incorrect...

the exponent does not apply to the 10, only to the base of e

so ...

e^(3x-7) = 5/10= .5

now take ln of both sides

(3x-7) ln e = ln .5 , but ln e = 1

3x-7 = ln .5

3x = 7 + ln .5

x = (7 + ln .5)/3 , and it is button-pushing time

## Answer This Question

## Related Questions

- Alg - Does log eqaul to baswe 10? So would logb=a be rewritten as 10^a=b? AND ...
- calc - given that ln2=0.7 and ln5=1.6, find: 1) ln(1/25) 2) e^3ln2 - ln5
- alg 2. - when condensing this expression why is the answer ln5. ln25-ln5
- Astronomy - The hottest stars have surface temperatures of about 40,000 K. At ...
- Exponential Equations - HOw would you solve this equation 5^x+6=4 Correct me if ...
- Chemistry - .50 - x / x = 3.20e-1 I need to solve for x. I was going to do .50 ...
- Chemistry(Please check) - .50 - x / x = 3.20e-1 I need to solve for x. I was ...
- Math/Algebra HELP - Can you please check these answers: 1. If the first Now= -9...
- Chemistry - 1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s) [N2O] = 0.383 M I ...
- Math(Thank you for your help) - 1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s...

More Related Questions