Posted by **Michael** on Monday, April 9, 2012 at 1:43am.

Suppose that the scores of architects on a particular creativity test are normally distributed. Using a normal curve table, what percentage of architects have Z scores (a) above .10, (b) below .10, (c) above .20, (d) below .20, (e) above 1.10, (f) below 1.10, (g) above -.10, and (h) below -.10?

- Statistics -
**PsyDAG**, Monday, April 9, 2012 at 10:29am
You need to know the mean and standard deviation.

Z = (score-mean)/SD

- Statistics (Oooops) -
**PsyDAG**, Monday, April 9, 2012 at 11:21am
My goof. All you need to do is find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion and its Z score.

- Statistics -
**Joe**, Friday, July 25, 2014 at 1:01pm
18. Suppose that the scores of architects on a particular creativity test are normally distributed. Using a normal curve table, what percentage of architects have Z scores:

Above .10?

Below .10?

Above .20?

Below .20?

Above 1.10?

Below 1.10?

Above -.10?

Below -.10?

You need to know the mean and standard deviation.

Z = (score-mean)/SD

- Statistics -
**Chris**, Wednesday, November 19, 2014 at 12:48pm
Suppose that the scores of architects on a particular creativity test are normally distributed. Using a normal curve table, what percentage of architects have Z scores:

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