Thursday

December 18, 2014

December 18, 2014

Posted by **Michael** on Monday, April 9, 2012 at 1:43am.

- Statistics -
**PsyDAG**, Monday, April 9, 2012 at 10:29amYou need to know the mean and standard deviation.

Z = (score-mean)/SD

- Statistics (Oooops) -
**PsyDAG**, Monday, April 9, 2012 at 11:21amMy goof. All you need to do is find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion and its Z score.

- Statistics -
**Joe**, Friday, July 25, 2014 at 1:01pm18. Suppose that the scores of architects on a particular creativity test are normally distributed. Using a normal curve table, what percentage of architects have Z scores:

Above .10?

Below .10?

Above .20?

Below .20?

Above 1.10?

Below 1.10?

Above -.10?

Below -.10?

You need to know the mean and standard deviation.

Z = (score-mean)/SD

- Statistics -
**Chris**, Wednesday, November 19, 2014 at 12:48pmSuppose that the scores of architects on a particular creativity test are normally distributed. Using a normal curve table, what percentage of architects have Z scores:

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