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January 25, 2015

Posted by **JOHN** on Monday, April 9, 2012 at 12:25am.

- physics -
**Elena**, Monday, April 9, 2012 at 8:49amHeat of fusion is the amount of heat energy required to change the state of a substance from solid to liquid.

λ = 335000 J/kg is heat of fusion of water-ice

c = 4185.5 J/(kg•K) is heat capacity of water

Q1 = λ•m1

Q2 =c•m1 •(t-t1) =c•m1•t

Q3 = c•m2 •(t2-t) .

Q1+Q2 = Q3

λ•m1 + c•m1•t = c•m2 •(t2-t),

λ•m1 + c•m1•t = c•m2 •t2 - c•m2 •t,

c•m1•t+ c•m2 •t = c•m2 •t2 - λ•m1

t = (c•m2•t2 - λ•m1)/[c•(m1+m2)] =( 4 180•0.318•18.2 -335000•0.055)/[4180•(0.335•0.055)] = 3.7 oC

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