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February 28, 2015

February 28, 2015

Posted by **Trisha** on Sunday, April 8, 2012 at 7:02pm.

- Applied Calculus -
**bobpursley**, Sunday, April 8, 2012 at 7:25pmarea=LW

L=800/W

Cost=3*2W+5L

cost=6W+4000/W

dcost/dw= 0=6-4000/W^2

W=sqrt(4000/6)

L= 800/W

- Applied Calculus -
**Trisha**, Sunday, April 8, 2012 at 7:56pmThank you, I got a very similar trying to do it the way our homework assignments were done. But your way seems much simpler. I got 25.8198898 by 30.76923077.

C=3x+3x+5y

=6x+5y

xy=800

y=800/x

c(x)=6x+5(800/x)

=6x+4000/x

c'(x)=6-4000/x^2

Find the critical value

6-4000/x^2=0

6=4000/x^2

6x^2=4000

x^2=4000/6

x^2=666.6666667

x=25.81988898

c"(x)=8000/x^3

C"(26)=8000/26^3

=.4551661356

xy=800

26y=800

y=800/26

y=30.76923077

The dimensions would by 26ft by 31ft.

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