AgNO3+NaCL=NaNo3+AgCl
heat change=-36
heat of percipitation of 2 moles of AgCl???
To calculate the heat of precipitation of 2 moles of AgCl, we can use the heat change and the balanced equation of the reaction.
The given balanced equation for the reaction is: AgNO3 + NaCl → NaNO3 + AgCl
From the balanced equation, we can see that every 1 mole of AgNO3 reacts with 1 mole of NaCl to produce 1 mole of AgCl.
Since the heat change for the reaction is given as -36 (without specifying the unit), we can assume it represents the heat change in kilojoules (kJ).
To find the heat of precipitation of 2 moles of AgCl, we need to apply stoichiometry. We know that the heat change for 1 mole of reaction is -36 kJ. Therefore, we can calculate the heat change for 2 moles of reaction using the following equation:
Heat change for 2 moles of AgCl = (-36 kJ) * (2 moles of AgCl / 1 mole of reaction)
Heat change for 2 moles of AgCl = -72 kJ
Therefore, the heat of precipitation for 2 moles of AgCl is -72 kilojoules (kJ).