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May 25, 2015

Homework Help: Chemistry

Posted by Please Check! on Sunday, April 8, 2012 at 4:55pm.

4. Use the information above to write net ionic equations for the two reactions that you have observed.

5. For each reaction, write the two half-reactions that make it up and calculate the overall reaction potential by adding the two half-reactions. Each overall potential should be positive in order for the reactions to occur spontaneously.


4. 2 HgCl2 (aq) + SnCl2 (aq) --> SnCl4 (aq) + Hg2Cl2 (s)
Hg2Cl2 (aq) + SnCl2 (aq) --> 2 Hg (s) + SnCl4 (aq)

5.
2 Hg(l) + 2 e⁻ --> Hg⁺ E₀ = -0.79 V
Sn⁺ + 2 e⁻ --> Sn⁺ E₀ = 0.15 V
Total: -0.64 V


Sn⁺ + 2 e⁻ --> Sn⁺ E₀ = -0.15 V
Hg⁺ + 2 e⁻ --> 2 Hg(l) E₀ = 0.79 V
Total: 0.64 V

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