Posted by Marc on Sunday, April 8, 2012 at 2:49pm.
A bullet of mass m = 5.89 g is fired into a block of mass M = 3.09 kg that is initially at rest on the edge of a smooth table. (The table top is 0.83 m above the floor.) The bullet ends up stuck in the block, and together they fly off the table and fall to the floor.
If the bullet has an initial speed of 870 m/s, what distance D will the block travel horizontally before landing on the floor?

physics  Elena, Sunday, April 8, 2012 at 3:36pm
m•v= (m+M) •V,
V = m•v/(m+M) = 5.89•10^3•870/(5.89•10^3+3.09) =
=1.294 m/s.
h=g•t^2/2 ,
t = sqrt(2•h/g) = sqrt(2•0.83/9.8) =
= 0.412 s,
D = V•t = 1.294•0.412 = 0.53 m.
Answer This Question
Related Questions
 college physics  a bullet of mass 8g is fired into a block of mass 260g that is...
 physics  A bullet of mass m=10 g is fired with initial speed vi = 400 m/s into ...
 Physics  A block of mass m 1 sits at rest on a table over a hole in the table. ...
 physics  An 8.00 g bullet is fired into a 250 g block that is initially at rest...
 physics  An 8.00 g bullet is fired into a 160 g block that is initially at rest...
 physics  An 8.00 g bullet is fired into a 160 g block that is initially at rest...
 physics  An 8.00 g bullet is fired into a 160 g block that is initially at rest...
 physics  An m1 = 8.40 g bullet is fired into a m2 = 2.17 kg block that is ...
 physics  An 8.00 g bullet is fired into a 180 g block that is initially at rest...
 physics  An 8.64g bullet is fired into a 365g block that is initially at rest ...
More Related Questions