Posted by **Jake** on Sunday, April 8, 2012 at 3:34am.

Which plane goes through the origin and is perpendicular to the line r=(2,-2,1) + s(2,3,-4), seR?

a) 2x-2y+z=0

b) 2x+3y-4z=0

c) 2x+3y+z-4=0

d) none of the above.

I got D, none of the above. I have substituted and couldn't find the answer equal to zero.

- Calculus -
**Reiny**, Sunday, April 8, 2012 at 7:55am
1.

The line has direction numbers (2,3,-4)

The direction numbers of the normal of plane b)

are (2,3, -4)

Since the normal is perpendicular to the plane

the given line is perpendicular to the plane

2.

Does (0,0,0 satisfy the equation of plane b) ?

LS = 2(0) + 3(0) - 4(0) = 0

RS = 0 , so YES, it does

your correct answer is b)

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