Posted by Hannah on Saturday, April 7, 2012 at 10:54pm.
You want to find Kb for acetate. That is Kw/Ka and Ka is for acetic acid.
ok thank you!
so for Kb
So for Kb I did kw/ka = 1.0e-14/1.8e-5 = 5.55e-10 . Now I would multiply this by 5.06e-6 and take the square root and then covert to pH by taking the -log. Is this correct?
Yes, however the number is 5.06E-2 and not -6. Note, too, that a quadratic may be necessary. You will substitute 0.0506-x for (acetate) in the equation and the x may (or may not) be negligible.
I set this up as 5.55e-10 = x^2/0.0506-x
After converting to pH I got 5.27 but it said that this was incorrect so maybe I do need to use a quadratic, but I am not sure how to go about this.
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