Posted by **Jason** on Saturday, April 7, 2012 at 8:00pm.

if f varies jointly as q^2 and h, and if f = 72 when q = 3 and h = 4, find h when f = 48 and q = 2

- Interediate algebra -
**Reiny**, Saturday, April 7, 2012 at 10:32pm
f = khq^2 , where k is a constant

given: f = 72 , q=3 , h=4

72 = k(4)(9)

k = 2

so f = 2hq^2

when f=48 , and q=2

48 = 2h(4)

h = 6

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