Posted by Jason on Saturday, April 7, 2012 at 8:00pm.
if f varies jointly as q^2 and h, and if f = 72 when q = 3 and h = 4, find h when f = 48 and q = 2

Interediate algebra  Reiny, Saturday, April 7, 2012 at 10:32pm
f = khq^2 , where k is a constant
given: f = 72 , q=3 , h=4
72 = k(4)(9)
k = 2
so f = 2hq^2
when f=48 , and q=2
48 = 2h(4)
h = 6
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