Friday

November 21, 2014

November 21, 2014

Posted by **F0reveryoung** on Saturday, April 7, 2012 at 1:59pm.

Find the probability distribution for

Number of Red Balls:

0 =

1 =

2 =

3 =

- Probability Distribution -
**Priscilla**, Saturday, April 7, 2012 at 2:41pmtotal amount of balls = 15 red + 19 white = 34 balls

0 - 0/34 = 0

1 - 1/34

2 - 2/34 = 1/17

3 - 3/34

- Probability Distribution -
**Reiny**, Saturday, April 7, 2012 at 2:43pmProb red = 15/34

prob white = 19/34

when picking three:

prob(0 red) = C(3,0) (19/34)(18/33)(17/32) = 57/352

prob(1 red) = C(3,1) (15/34)(19/33)(18/32) = 2565/5984

prob(2red) = C(3,2) (15/34)(14/33)(19/32) = 1998/5984

prob (3red) = C(3,3)(15/34)(14/33)(13/32) = 455/5984

notice that the sum of the 4 fractions above is 5984/5984 = 1

- typo - Probability Distribution -
**Reiny**, Saturday, April 7, 2012 at 2:44pmthe 2nd last prob calculation should be 1995/5984

**Answer this Question**

**Related Questions**

Finite Math - An urn contains sixteen red balls and seventeen white balls. A ...

Finite Math-Probability - Suppose we have an urn with 10 white balls and 6 red ...

Math-Probability - An urn contains four red balls and three white balls. A ...

statistics - An urn contains 10 balls of which 6 are white, 3 are red and 1 is ...

Finite Math - An urn contains six red balls and five white balls. A sample of 2 ...

Strayer University - An urn contains white balls and red balls. If Juan chooses ...

maths - urn contains 4 white and 6 red rolls. Four balls are drawn at random (...

Statistic - A urn contains 21 red balls, 14 white balls If we randomly select 2 ...

math probability - Four balls are selected at random without replacement from ...

probability - Four balls are selected at random without replacement from an urn...