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September 20, 2014

September 20, 2014

Posted by **Jake** on Saturday, April 7, 2012 at 1:35pm.

a) 2x + 3y - 7=0, -3x - 2y + 2=0

b) 2x - 3y + 2=0, 5x - 7y + 2=0

c) -4x + y - 3=0, x + 4y=0

d) -5x + y + 1=0, 5x + y + 1=0

Please explain. I know we have to use the dot product :3

- Calculus -
**Reiny**, Saturday, April 7, 2012 at 2:59pmfor any ax + by + c = 0 , the direction vector of the normal is (a,b)

If the normals are perpendicular, then obviously the line are perpendicular, so ...

a)

normal to first line is (2,3)

normal to 2nd line is (-3,-2)

dot product = -6 - 6 ≠ 0

so the lines are NOT perpendicular.

do the others the same way.

If you get a dot product of zero , they are perpendicular.

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