If the strip is 28 mm long, how far is the maximum deviation of the strip from the straight orientation? (The deviation is measured from the straight orientation from the interface of the two strips.) Radius of curvature is 53.7
L= 28 mm, R = 53 (units?)
Central angle is φ = L/R.
The deviation is
d = R•sin(φ/2)•tan(φ/2).
doesnt give the right answer
To determine the maximum deviation of the strip from the straight orientation, we need to consider the radius of curvature. In this case, the radius of curvature is given as 53.7.
The maximum deviation occurs at the point where the strip is farthest from the straight orientation, which is at the center of the strip. In other words, the maximum deviation corresponds to half the length of the strip.
Given that the strip is 28 mm long, the maximum deviation will then be half of this length, which is 28 mm/2 = 14 mm.
Therefore, the maximum deviation of the strip from the straight orientation, measured from the interface of the two strips, is 14 mm.