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March 28, 2017

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.050 mole of weak acid (HA) is dissolved in enough water to make 1.0 L of solution. The pH of this solution is 3.50. What is the value of Ka for this weak acid?

  • Chemistry - ,

    ...........HA ==> H^+ + A^-
    initial..0.05M......0....0
    change....-x........x....x
    equil....0.05-x.....x....x

    Ka = (H^+)(A^-)/(HA)
    Start with pH and convert that to H^+ (which is x in the above), subsubstitute into the Ka expression and solve for Ka.

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