Posted by Mike on Thursday, April 5, 2012 at 11:42pm.
Law of Cosines:
cosB = (a^2+c^2-b^2)/2ac.
cos38 = ((110)^2+(136)^2-b^2) / 29920.
0.7880 = (30596-b^2) / 29920.
Cross multiply:
30,596-b^2 = 0.7880*29920 = 23576.96.
-b^2 = 23,976.96-30596 = -6619.04.
b^2 = 6619.04.
b = 81.36.
Law of Sines:
sinA/a = sinB/b.
sinA / 110 = sin38 / 81.36.
Multiply both sides by 110:
sinA = 110(sin38 / 81.36) = 0.832384.
A = 56.34 Deg.
C = 180 - 38 - 56.34 = 85.66 Deg.
Related Questions
Trig Help Please!!! - Find the indicated angle è. (Use either the Law of ...
Pre-Calc Helppp!!! - Use the Law of Sines to solve for all possible triangles ...
Algebra 2 - Using the information given about a triangle, which law must you use...
pre calc - the longest side of a triangle is 34 feet. the measures of two angles...
Law of cosines - A tree on a hillside casts a shadow 215 ft down the hill. If ...
Pre-Cal - Use the law of cosines to find the angle of Q between the given ...
pre-Cal(Please help) - Use the law of cosines to find the angle Q between the ...
math - solve each triangle using either the Law of Sines or the Law of Cosines. ...
Physics - i was woundering if you could point in the right direction i'm ...
Trig - Should the triangle be solved beginning with Law of Sines of Law of ...
For Further Reading