Posted by micheal Garcia on Thursday, April 5, 2012 at 8:07pm.
Let no. of dimes = x.
Then, no. of quarters = x + 3 and no. of nickels = x - 5.
Total no. of coins = x + (x + 3) + (x - 5).
This value is equal to 52.
So, x + (x + 3) + (x - 5) = 52
or x + x + 3 + x - 5 = 52
or 3x - 2 = 52
or 3x = 52 + 2 = 54
or x = 54/3 = 18
So Sal have 18 dimes
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