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physics

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A clock has an aluminum pendulum with a period of 1.000 s at 20.3 °C. Suppose the clock is moved to a location where the average temperature is 28.1 °C. (The linear expansion coefficient for aluminum is 2.20 10-5 °C−1.)
(a) Determine the new period of the clock's pendulum. (Enter your answer to six siginficant figures.)
(b)Determine how much time the clock will lose in 2 weeks.

  • physics - ,

    There are two standard equations here: what is it you have a question about?

  • physics - ,

    what equations do i use?

  • physics - ,

    a.
    Moment of inertia respectively the axis
    that passes through the end of the pendulum is
    I = Io+mx^2 = mL^2/12 + mL^2/4 = mL^2/3.
    T1 = sqrt(I/m•g•x) = sqrt( mL^2/3m•g•x)
    =sqrt( L^2/3•g•x) = L/sqrt(3•g•x) =1 s.
    L = sqrt(3•g•x),
    α =ΔL/(L•ΔT),
    ΔL = α •sqrt(3•g•x) • ΔT,
    T2 = sqrt ((L+ ΔL)^2/3•g•x) =
    =(L+ΔL)/ sqrt(3•g•x)=
    = (L + α •sqrt(3•g•x) • ΔT)/ sqrt(3•g•x) =
    = ( sqrt(3•g•x) + α •sqrt(3•g•x) • ΔT)/ sqrt(3•g•x)=
    = 1+7.8•2.2•10^-5 = 1.000172 s.
    b.
    Δto= 0.000172 s.
    Δt =0.000172•3600•24•14 = 208.0512 s.

  • physics - ,

    can you help more, i didn't get the right answer..i didn't get where you got 7.8 from

  • physics - ,

    ΔT = 28.1 -20.3 = 7.8 oC

  • physics - ,

    i didn't get the right answer

  • physics - ,

    What is the right answer?

  • physics - ,

    i don't know

  • physics - ,

    Why do you believe that this answer is incorrect?

  • physics - ,

    i get it wring when i enter it

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