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April 1, 2015

April 1, 2015

Posted by **Anonymous** on Thursday, April 5, 2012 at 2:36pm.

Center at (-2,3) with major axis of length 8 and parallel to the y axis, minor axis of length 2.

I dont understand how you get the formula for this. some help please

- Algebra 2 -
**Steve**, Thursday, April 5, 2012 at 3:00pmyou should know that an ellipse with center at (h,k) and axes 2a,2b is

(x-h)^2/a^2 + (y-k)^2/b^2 = 1

so, plug in your data. The only tricky part is knowing which are a and b. Since the major axis is parallel to the y-axis, (y-k)^2/b^2 will have the larger denominator.

(x+2)^2/1 + (y-3)^2/16 = 1

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