Posted by Anonymous on Thursday, April 5, 2012 at 2:36pm.
you should know that an ellipse with center at (h,k) and axes 2a,2b is
(x-h)^2/a^2 + (y-k)^2/b^2 = 1
so, plug in your data. The only tricky part is knowing which are a and b. Since the major axis is parallel to the y-axis, (y-k)^2/b^2 will have the larger denominator.
(x+2)^2/1 + (y-3)^2/16 = 1
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