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April 18, 2014

April 18, 2014

Posted by **Megan** on Thursday, April 5, 2012 at 1:33pm.

- physics -
**Elena**, Thursday, April 5, 2012 at 1:51pmk •q1 •q3/x^2 = k •q2 •q3/(d-x)^2

q1 •q3 (d-x)^2 = k •q2 •q3• x^2

Solve for x

- physics -
**Elena**, Thursday, April 5, 2012 at 1:55pmThe second line

q1 •q3 (d-x)^2 = q2 •q3• x^2

- physics -
**Megan**, Thursday, April 5, 2012 at 2:26pmElena, for some reason I'm getting an answer of -3

(8.00 x 10^-12) x (d-x)^2 = (6.00 x 10^-12) x (x^2)

(d-x)^2/x^2 = 7.5 x 10^-1

(d-x)(d-x)/x^2 = 7.50 x 10^-1

x^2-x+0.25/x^2= 7.50 x 10^-1

then I get x = -3

Can you help! I'm not sure where i am going wrong.

- physics -
**Elena**, Thursday, April 5, 2012 at 3:54pmq1 • (d-x)^2 = q2 • x^2

4•10^-9•(d-x)^2 = 3•10^-9•x^2

4(d^2 - 2•d•x + x^2) = 3•x^2,

x^2 - 4x + 1 = 0

x =2 ± sqrt(4-1) =2 ± 1.73.

x1 = 0.27 m, x2 =3.73m (falls out)

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