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April 20, 2014

April 20, 2014

Posted by **sol** on Thursday, April 5, 2012 at 10:07am.

f(x,y)= 4-2x-y; R{(x,y)0<x<1;0<y<2

- calculus -
**Steve**, Thursday, April 5, 2012 at 2:40pmthis is pretty straightforward. Nice rectangular base.

v = ∫∫R f(x,y) dA

= ∫[0,1]∫[0,2] 4-2x-y dy dx

= ∫[0,1] (4y - 2xy - 1/2 y^2)[0,2] dx

= ∫[0,1] (6-4x) dx

= (6x - 2x^2)[0,1]

= 4

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