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Posted by on Thursday, April 5, 2012 at 10:07am.

find the volume of the solid bounded above by the surface z=f(x,y) and below by the plane region R
f(x,y)= 4-2x-y; R{(x,y)0<x<1;0<y<2

  • calculus - , Thursday, April 5, 2012 at 2:40pm

    this is pretty straightforward. Nice rectangular base.

    v = ∫∫R f(x,y) dA
    = ∫[0,1]∫[0,2] 4-2x-y dy dx
    = ∫[0,1] (4y - 2xy - 1/2 y^2)[0,2] dx
    = ∫[0,1] (6-4x) dx
    = (6x - 2x^2)[0,1]
    = 4

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