Posted by Sheri on Thursday, April 5, 2012 at 8:56am.
Let x = solubility of Pb(OH)2 in mols/L.
Pb(OH)2 ==> Pb^2+ + 2OH^-
....x........x.......2x
Ksp = (Pb^2+)(OH^-)^2
Substitute from the chart above and solve for x, find 2x, then convert to pH.
? lost- what chart?
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