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November 25, 2014

November 25, 2014

Posted by **Dexter Gibons** on Thursday, April 5, 2012 at 1:34am.

altitude of 100 feet passes directly overhead. Thirty seconds later, what is the distance between me and

the balloon?

- Tech Math 1b -
**Steve**, Thursday, April 5, 2012 at 11:40am30 seconds = 30/3600 = 1/120 hour

in 1/120 hr, balloon has gone 15/120 = 1/8 mi = 660 ft

Now you have a right triangle, with legs 100 and 660

d^2 = 100^2 + 660^2 = 445600

d = 667.5 ft

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