Posted by Brian on Wednesday, April 4, 2012 at 11:45pm.
well, we know
4x+h = 96, so h=96-4x
v = hx^2
= x^2(96-4x)
= 96x^2 - 4x^3
= 4(24x^2 - x^3)
dv/dx = 4(48x - 3x^2)
= 12x(16 - x)
dv/dx = 0 when x = 0 or 16
so, h = 96-4*16 = 32
So, if the package is 16x16x32
v = 8192 in^3
Now, technically, 4x+h <= 96, but it should be clear that max volume occurs when 4x+h is as large as possible.
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