Posted by Richard on Wednesday, April 4, 2012 at 5:22pm.
Try a one-sample z-test.
Hypotheses:
Ho: µ = 42 -->null hypothesis
Ha: µ < 42 -->alternate hypothesis
z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size)
With your data:
z = (40.2 - 42)/(5/√36) = ?
Finish the calculation.
Check a z-table at the level you wish to use for the rejection region.
If the z-test statistic exceeds that value from the z-table, reject the null and conclude µ < 42. If the z-test statistic does not exceed the that value from the z-table, do not reject the null (you cannot conclude a difference).
I hope this will help get you started.
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