Wednesday

April 16, 2014

April 16, 2014

Posted by **Amanda** on Wednesday, April 4, 2012 at 4:57pm.

Age, x: 0.1, 0.2, 0.4, 0.7, 0.6, 0.9, 0.1, 0.2, 0.4, 0.9

Hours slept, y: 14.9, 14.5, 13.9, 14.1, 13.9, 13.7, 14.3, 13.9, 14.0, 14.1

Find the equation of the regression line. Then use the regression equation to predict the value of y for the given x, if meaningful. If it is not meaningful, explain why.

a. X-0.3years b. X=3.9years c. X=0.6years d. X=0.8years

- Statistics -
**MathGuru**, Wednesday, April 4, 2012 at 7:57pmIf you need to show the work by hand, you can develop the regression equation in the following format:

predicted y = a + bx

...where a represents the y-intercept and b the slope.

To get to that point, here are some formulas to calculate along the way.

To find a:

a = (Ey/n) - b(Ex/n)

Note: E here means to add up or to find the total.

To find b:

b = SSxy/SSxx

To find SSxy:

SSxy = Exy - [(Ex)(Ey)]/n

To find SSxx:

SSxx = Ex^2 - [(Ex)(Ex)]/n

Once you have the equation, substitute the values for x and solve for predicted y.

I hope this will help get you started.

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