Statistics
posted by Mike on .
Data from the latest census was analyzed. It was determined that oneparent households spend less on food away from home that do twoparent households. The mean amount spent by 30 oneparent households is $1876 and the standard deviation is $113. The mean amount spent by 30 twoparent households is $1878 and the standard deviation is $85. At a a=0.05 can you support this conclusion?

Try an independent groups ttest.
Hypotheses:
Ho: µ1 = µ2 >null hypothesis
Ha: µ1 < µ2 >alternate hypothesis
Use (n1 + n2  2) degrees of freedom for this test. Use a ttable to determine your cutoff or critical value to reject the null using 0.05 level of significance for a onetailed test. If your test statistic exceeds the critical value from the table, reject the null and conclude a difference (µ1 < µ2). If the test statistic does not exceed the critical value from the table, do not reject the null.
I hope this will help get you started.