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November 23, 2014

November 23, 2014

Posted by **kathy** on Wednesday, April 4, 2012 at 2:34pm.

- algebra -
**Steve**, Wednesday, April 4, 2012 at 2:47pmI'll work with the width, since the letter l and the digit 1 look similar.

if the length is 3 more than the width,

w(w+3) = 54

w^2 + 3w = 54

w^2 + 3w - 54 = 0

(w+9)(w-6) = 0

w=6 (can't have negative width)

the rectangle is 6x9

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