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algebra

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The width of a rectangle is 3 cm less than the length. The area of the rectangle is 54 square cm. Find the width and length of the rectangle.

  • algebra - ,

    I'll work with the width, since the letter l and the digit 1 look similar.
    if the length is 3 more than the width,

    w(w+3) = 54
    w^2 + 3w = 54
    w^2 + 3w - 54 = 0
    (w+9)(w-6) = 0

    w=6 (can't have negative width)

    the rectangle is 6x9

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