The specific heat of iron is approximately 0.45 J/g °C. How much heat energy is required to raise a 40 g sample of aluminum from 40 °C to 60 °C?
To calculate the heat energy required to raise a sample of aluminum, you can use the formula:
Q = m * c * ΔT
Where:
Q = heat energy (in Joules)
m = mass of the sample (in grams)
c = specific heat capacity (in J/g °C)
ΔT = change in temperature (in °C)
Given:
m = 40 g
c = 0.45 J/g °C
ΔT = 60 °C - 40 °C = 20 °C
Now, substitute the given values into the formula and calculate:
Q = 40 g * 0.45 J/g °C * 20 °C
Q = 900 J
Therefore, it would require 900 Joules of heat energy to raise the 40 g sample of aluminum from 40 °C to 60 °C.
To find the heat energy required to raise the temperature of a substance, you can use the formula:
Q = m * c * ΔT
Where:
Q is the heat energy (in Joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in J/g °C)
ΔT is the change in temperature (in °C)
In this case, the mass of the aluminum sample is 40 g, the specific heat capacity of iron is 0.45 J/g °C, and the change in temperature is 60 °C - 40 °C = 20 °C.
Plugging in the values into the formula, we get:
Q = 40 g * 0.45 J/g °C * 20 °C
Q = 360 J
Therefore, the heat energy required to raise the 40 g sample of aluminum from 40 °C to 60 °C is 360 Joules.
q = mass x specific heat x (Tfinal-Tinitial)
Note that you list the specific heat Fe but ask for how much heat is required to heat Al. You may have mixed two problems.