Posted by **Jassie** on Wednesday, April 4, 2012 at 11:43am.

How many codes consisting of a letter followed by 3 digits can be made if no digit can be used more than once?

- Math -
**bobpursley**, Wednesday, April 4, 2012 at 12:27pm
26*10*9*8

This assumes the letter "O" is allowed. Often it is not, because of confusion with zero. IT also assumes case of the letters is indifferent. If case masters, then A and a will be different, so you double the number of codes available.

- Math -
**Jassie**, Wednesday, April 4, 2012 at 4:37pm
can you tell me how you got 9 and 8?

I get it 26 alphabets.

10 digits.

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