Post a New Question

chemistry

posted by .

a 0,25M solution of a week acid is 3% dissociated.calculate ka

  • chemistry -

    0.25 x 0.003 = 7.5E-4
    ..............HA ==> H^+ + A^-
    initial.......0.25.....0.....
    change.....-7.5E-4...7.4E-4..7.5E-4
    equl..........?........?......?

    Ka = (H^+)A^-)/(HA)
    Substitute and solve for Ka.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question