Post a New Question

Algebra

posted by .

R varies jointly as r and B^2. When r=3, and B=3 R=135. Find R when r is 1
and B=10.

  • Algebra -

    R = krB^2
    135 = k(3)(3^2) = 27k
    k = 5

    So, R(r,B) = 5rB^2
    R(1,10) = 5(1)(100) = 500

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question