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posted by Taurus Tuesday, April 3, 2012 at 11:18pm.

R varies jointly as r and B^2. When r=3, and B=3 R=135. Find R when r is 1 and B=10.

R = krB^2 135 = k(3)(3^2) = 27k k = 5 So, R(r,B) = 5rB^2 R(1,10) = 5(1)(100) = 500

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