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December 20, 2014

December 20, 2014

Posted by **jessica** on Tuesday, April 3, 2012 at 9:50pm.

- algebra -
**Steve**, Wednesday, April 4, 2012 at 10:29amJust do the long division to get

(2y^4 + z^2)(4y^8 - 2y^4z^2 + z^4)

- algebra -
**Steve**, Wednesday, April 4, 2012 at 10:31amor, you could recognize it as the sum of two cubes:

8y^12+z^6

= (2y^4)^3 + (z^2)^3

= (2y^4 + z^2)((2y^4)^2 - (2y^4)(z^2) + (z^2)^2)

= (2y^4 + z^2)(4y^8 - 2y^4z^2 + z^4)

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