Posted by **carlton** on Tuesday, April 3, 2012 at 9:08pm.

Suppose that a department contains 10 men and 17 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men?

- discrete math -
**MathMate**, Tuesday, April 3, 2012 at 9:22pm
To choose 5 women and 1 man, there are

(17,5)*(10,1) ways.

Figure out the number of ways to choose

6 women,

4 women and 2 men,

and add up the total number of ways.

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