Posted by **Lala** on Tuesday, April 3, 2012 at 6:54pm.

I'm trying to put this parabola in standard form which is: (y-k)^2=4p(x-h)

The equation is x=(1/12)(y-2)^2 +6

Here is what i have so far:

x=(1/12)(y-2)^2 +6

-6 -6

x-6=(1/12)(y-2)^2

*12 *12

Would it be

12x-6 OR 12x-72?

thanks

- Pre-Cal -
**Reiny**, Tuesday, April 3, 2012 at 7:06pm
from

x-6=(1/12)(y-2)^2

multiply both sides by 12

12(x-6) = (y-2)^2 , which of course is

(y-2)^2 = 12(x-6) , leave it like that, or you lose the form requested.

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