Posted by Lala on Tuesday, April 3, 2012 at 6:54pm.
I'm trying to put this parabola in standard form which is: (y-k)^2=4p(x-h)
The equation is x=(1/12)(y-2)^2 +6
Here is what i have so far:
Would it be
12x-6 OR 12x-72?
- Pre-Cal - Reiny, Tuesday, April 3, 2012 at 7:06pm
multiply both sides by 12
12(x-6) = (y-2)^2 , which of course is
(y-2)^2 = 12(x-6) , leave it like that, or you lose the form requested.
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