Sunday

March 29, 2015

March 29, 2015

Posted by **Lala** on Tuesday, April 3, 2012 at 6:54pm.

The equation is x=(1/12)(y-2)^2 +6

Here is what i have so far:

x=(1/12)(y-2)^2 +6

-6 -6

x-6=(1/12)(y-2)^2

*12 *12

Would it be

12x-6 OR 12x-72?

thanks

- Pre-Cal -
**Reiny**, Tuesday, April 3, 2012 at 7:06pmfrom

x-6=(1/12)(y-2)^2

multiply both sides by 12

12(x-6) = (y-2)^2 , which of course is

(y-2)^2 = 12(x-6) , leave it like that, or you lose the form requested.

**Answer this Question**

**Related Questions**

pre cal - write the standard form equation of the parabola with vertex (-2,-2) ...

pre cal - find the standard form of the equation of a parabola with the vertex (...

Precalc - How would I put this parabola in standard form: x^2-6x+8y-31 Here how ...

Parabola - How do I put this parabola in standard form? Could someone show how ...

Algebra 2 - I have a question and I can not figure it out. Any answers to the ...

Pre-cal - Find the vertex of y^2 + 4y + 2x +10 = 0. Use completing the square to...

Pre-Cal - how do we put x^2-2y^2=4 into a standard equation???

Algebra - I know that standard form is Ax+By=C, but I'm not really sure how to ...

Pre-cal - Sketech the graph of the equation y^2+4y+2x+10=0. Identify the vertex...

Pre calc - Write the equation in standard parabola form? x^2+ 4xy +4y^2 +5root5 ...