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March 4, 2015

March 4, 2015

Posted by **Joe** on Tuesday, April 3, 2012 at 5:53pm.

- Calculus -
**MathMate**, Tuesday, April 3, 2012 at 8:48pmThe idea behind the approximation is:

y(x)=1/x

y'(x)=-1/x²

Let x=x0+Δx

y(x) = y(x0)+y'(x0)*Δx

=y(x)-Δx / (x0 ²)

Now apply x0=0.5, Δx=0.004

y(0.504)=y(0.5)-0.004/0.5²

=2-0.016

=1.984

compare to approximate actual value of

1.984126984126984

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