Posted by Anonymous on .
Create a (simplified) rational function that has the following asymptotes.(show work) y=0, x=3, x=0, and x=2

MathLog#4 
bobpursley,
Hmmmm. f(x)= e^x * 1/[(x+3)(x)(x2)]

MathLog#4 
Steve,
I think rational functions are ratios of polynomials, so forget the e^x and just use
1/[(x+3)(x)(x2)]
or, the numerator could be any polynomial of degree less than 3. It will still approach y=0 as x gets large.