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November 27, 2014

November 27, 2014

Posted by **Anonymous** on Tuesday, April 3, 2012 at 5:13pm.

- MathLog#4 -
**bobpursley**, Tuesday, April 3, 2012 at 5:30pmHmmmm. f(x)= e^-x * 1/[(x+3)(x)(x-2)]

- MathLog#4 -
**Steve**, Tuesday, April 3, 2012 at 5:38pmI think rational functions are ratios of polynomials, so forget the e^-x and just use

1/[(x+3)(x)(x-2)]

or, the numerator could be any polynomial of degree less than 3. It will still approach y=0 as x gets large.

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