Posted by Anonymous on Tuesday, April 3, 2012 at 3:38pm.
If a(t) is the amount of C14 after t years,
a(t) = .05 * 2^(-t/5700)
do you see why this works? every 5700 years, the exponent of t decreases by 1, from 0 to -1 to -2, etc. making the multiplier 1, 1/2, 1/4, ...
a(5700) = .05*2^(-1) = .025
a(11400) = .05*2^(-2) = .0125
and so on
ME SO HORNY.
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