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March 30, 2015

March 30, 2015

Posted by **Anonymous** on Tuesday, April 3, 2012 at 3:38pm.

- algebra -
**Steve**, Tuesday, April 3, 2012 at 5:15pmIf a(t) is the amount of C14 after t years,

a(t) = .05 * 2^(-t/5700)

do you see why this works? every 5700 years, the exponent of t decreases by 1, from 0 to -1 to -2, etc. making the multiplier 1, 1/2, 1/4, ...

a(5700) = .05*2^(-1) = .025

a(11400) = .05*2^(-2) = .0125

and so on

- algebra -
**Morgan Freeman**, Thursday, May 10, 2012 at 1:00pmME SO HORNY.

- algebra -
**Anonymous**, Wednesday, March 11, 2015 at 9:19am13300

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