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October 1, 2014

October 1, 2014

Posted by **Anonymous** on Tuesday, April 3, 2012 at 2:13pm.

This is what I got:

Quotient: 2x^4+4x^3+x^2-3x-6

Remainder: -11

Do i just leave the quotient like this: 2x^4+4x^3+x^2-3x-6?

Do I need to factor it down more?

please help and thank you

- Math -
**Reiny**, Tuesday, April 3, 2012 at 2:41pmYour division is correct

Since you have a remainder, the expression cannot be properly factored

the best you can so is say ...

(2x^5-7x^3-5x^2+1)/(x-2) = 2x^4+4x^3+x^2-3x-6 - 11/(x-2)

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