Friday

March 6, 2015

March 6, 2015

Posted by **Tiffany** on Monday, April 2, 2012 at 10:33pm.

- calculus -
**Reiny**, Monday, April 2, 2012 at 11:41pmLet the coordinates of the ship be P(x,y)

so AP =2 and BP=5

√(x^2+y^2) = 2

x^2+y^2 = 4 , (#1)

√( (x^2 + (y-6)^2 ) = 5

x^2 + y^2 - 12y + 36 = 25

x^2 + y^2 - 12y = -11 , (#2)

#1 - #2 :

12y = 15

y = 15/12 = 5/4 = 1.25

then in #1:

x^2 + 225/144 = 4

x^2 = 39/16

x = ± √39/4

The ship could be at (√39/4 , 5/4) or (-√39/4 , 5/4)

**Answer this Question**

**Related Questions**

Calculus - The captain of a ship at sea sights a lighthouse which is 260 feet ...

trig - The captain of a ship at sea sights a lighthouse which is 280 feet tall. ...

trig - The captain of a ship at sea sights a lighthouse which is 120 feet tall. ...

trigonometry - A ship is sighted directly east of a lighthouse. Another ship, ...

Algebra - Sorry for asking another question, but I don't know how to set this ...

trig - a lighthouse is located at point A. a ship travels from point B to point ...

pre-calc - two lighthouses A and B are positioned along the coast.A ship is ...

Mathamatics - A ship is due south of a lighthouse. It sails on a bearing of 72* ...

trigonometry - The bearing of the lighthouse is N 68 degress E from a ship 43 ...

maths - A ship sailing on a course bearing 036 degrees is 5500 metres due south...