Hi, I need help with these questions:

factor
6m^2-90m+324
8a62-2ab-21b^2
pls help

a) 6(m^2-15m+54)=6(m-9)(m-6)

b) (4a -7b)(2a+3b)

your teacher is too easy.

I still don't get how you got the answer to the second question. Can you explain please

Of course! I can help you factor these expressions. To factor an expression, we try to find two binomial expressions that, when multiplied together, give us the original expression.

Let's start with the first expression: 6m^2 - 90m + 324.

Step 1: Look for a common factor. In this case, all three terms have a common factor of 6.
6m^2 - 90m + 324 = 6(m^2 - 15m + 54)

Step 2: We need to find two numbers that add up to -15 (the coefficient of the middle term) and multiply to 54 (the constant term). In this case, -6 and -9 fulfill these conditions since -6 + (-9) = -15 and -6 * (-9) = 54.
6(m^2 - 15m + 54) = 6(m - 6)(m - 9)

So, the factored form of 6m^2 - 90m + 324 is 6(m - 6)(m - 9).

Now let's move on to the second expression: 8a^2 - 2ab - 21b^2.

Step 1: Look for a common factor, if any. In this case, we can't simply factor out a common factor from all three terms.

Step 2: We need to find two numbers that multiply to -21 (the coefficient of the last term) and add up to -2 (the coefficient of the middle term). In this case, -7 and +3 fulfill these conditions since -7 * 3 = -21 and -7 + 3 = -4.
8a^2 - 2ab - 21b^2 = (4a - 7b)(2a + 3b)

Therefore, the factored form of 8a^2 - 2ab - 21b^2 is (4a - 7b)(2a + 3b).

I hope this explanation helps you understand how to factor these expressions. Let me know if there's anything else I can assist you with!