Posted by **ssssss** on Monday, April 2, 2012 at 8:35am.

Paul has 3 pieces of rope of length 36cm,40cm,and 48cm respectively. He needs to select 2 out of the 3 pieces and cut them into smaller pieces of equal length. What is the greatest possible length of each smaller piece if there is to be no wastage?

- MATHS -
**bobpursley**, Monday, April 2, 2012 at 8:53am
why wouldn't he take the longest two, cut them into 36cm pieces?

- MATHS -
**Steve**, Monday, April 2, 2012 at 10:23am
I'd say it's because they are to be cut from 2 of the pieces. That is, which two ropes have the largest common factor?

36 = 12*3

40 = 8*5

48 = 12*4

Looks to me like 12cm is the longest piece that divides evenly 2 of the 3 original lengths.

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