Posted by lovemore on Monday, April 2, 2012 at 4:14am.
Use the Henderson-Hasselbalch equation to solve part 1.
For part 2, the conjugate base (we'll call the molarity M) is
............A^- + HOH ==> HA + OH^-
initial.....M..............0.....0
change......-x.............x.....x
equil......M-x.............x.....x
Kb for the A^- base = (Kw/Ka for the HA).
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