Posted by maga on Monday, April 2, 2012 at 12:48am.
∫[1,e^2]∫[1,e] lny/x dy dx
= ∫[1,e^2](y/x (lny - 1))[1,e] dx
= ∫[1,e^2] [(e/x (1-1))-(1/x (0-1))] dx
= ∫[1,e^2] 1/x dx
= lnx [1,e^2]
= 2
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