Posted by angel on .
A ray of light traveling in air strikes the surface of a liquid.
If the angle of incidence is 33.5◦
angle of refraction is 19.8◦, ﬁnd the critical
angle for light traveling from the liquid back
into the air.
Answer in units of◦
then, critical angle= arcsin n
do I put my calculator in degrees?
yes, I would.
I keep getting error
sinr1/sinr2 = n2/n1,
n1 = 1.003 (for air)
n2 = n1•( sinr1/sinr2) = 1.6244
sinr(o) = 1/n2 = 0.6156
r(o) – arcsin(0.6156) = 38 degr.